AGI Solution
Answer: AUTOMAGICAL GRADIENT IMPROVEMENTS
Each subplot corresponds to a character. The starting value of each plot is the character's ASCII value divided by 10, as hinted by the comment: "The loss curves look decimated at the start". This yields "ARTIFICIAL(L) GENERAL(T) INTELLIGENCE" as suggested by the title "AGI".
| A | R | T | I | F | I | C | I | A | L | L | |
| G | E | N | E | R | A | L | T | ||||
| I | N | T | E | L | L | I | G | E | N | C | E |
This approach is validated by the fact that the graphs corresponding to extra characters have NaN losses.
The graphs in the image all have integer differences between the starting and ending losses. Transcribing those differences, we get:
| 0 | 3 | 0 | 6 | 7 | -8 | 4 | 0 | 2 | -11 | NaN | |
| 0 | 13 | -13 | -1 | -9 | 4 | 2 | NaN | ||||
| 0 | -1 | -4 | 13 | 3 | 10 | -4 | 6 | 0 | 0 | 17 | 14 |
Take the corresponding letter and increment its ASCII representation by this amount to yield "AUTOMAGICAL GRADIENT IMPROVEMENTS".